TOPIC:

The following expression is accepted:
(RueckString usual)
if ( islogic(RueckString) .and. Rueckstring == true)

The following expression gives the error below
if ( islogic(RueckString) .and. Rueckstring)

Error In order for '__Usual.operator &(__Usual, __Usual)' to be applicable as a short circuit operator, its declaring type '__Usual' must define operator true and operator false

Unfortunately there are many places in our old VO code. Is it necessary to change all places?

Thank you
Arne Ortlinghaus

Arne,

This problem is fixed in our current development branch.
If you add a cast to your code then it works in Vulcan as well:

Unfortunately that cast will not work in VO.

Robert

Thank you
Arne